A completely submerged cube of volume 0.0008 m^3 is placed in water (ρ ≈ 1000 kg/m^3). What is the buoyant force acting on it?

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Multiple Choice

A completely submerged cube of volume 0.0008 m^3 is placed in water (ρ ≈ 1000 kg/m^3). What is the buoyant force acting on it?

Explanation:
The buoyant force equals the weight of the water displaced. Since the cube is fully submerged, the displaced volume is its entire volume: 0.0008 m^3. The mass of that displaced water is density times volume: 1000 kg/m^3 × 0.0008 m^3 = 0.8 kg. Its weight is 0.8 kg × g ≈ 0.8 × 9.8 m/s^2 = 7.84 N. So the buoyant force is about 7.84 newtons.

The buoyant force equals the weight of the water displaced. Since the cube is fully submerged, the displaced volume is its entire volume: 0.0008 m^3. The mass of that displaced water is density times volume: 1000 kg/m^3 × 0.0008 m^3 = 0.8 kg. Its weight is 0.8 kg × g ≈ 0.8 × 9.8 m/s^2 = 7.84 N. So the buoyant force is about 7.84 newtons.

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